MIC205B Exam 1 Key
September 20, 2007
Instructor: Dr. Stephen Billington
Part
1 MULTIPLE CHOICE: Read each question and the answers carefully. Circle the
correct answer on the test paper. Each correct answer is worth 3 points, for a
Part 1 total of 45 points. Correct answers are
underlined below
JUSTIFICATIONS: If you are unsure of an answer, you may write a short explanation next to the question on the test paper (this may earn you points if your answer is wrong, but you can justify it).
1.
Monosaccharides are joined
together using
a. ester linkages
b. glycosidic bonds
c. peptide bonds
d. crazy glue
2.
The primary structure of a protein
refers to
a. the three dimensional structure of the protein
b. the interactions of the protein with other proteins
c. the sequence of amino acids in the
protein
d. the presence of D-amino acids
3.
Nucleotides are composed of
a. a sugar, a nitrogenous base and a
phosphate
b. an amino acid, a nitrogenous base and a phosphate
c. a glycerol molecule and three fatty acids
d. two sugar molecules linked by a glycosidic bond
4. The
process of modifying a molecule after it diffuses into the cell to maintain a
concentration gradient is called
a. group translocation
b. passive diffusion
c. active transport
d. osmosis
5.
Long carbon chains that are
completely bonded to hydrogen are
a. unsaturated
b. liquid at room temperature
c. saturated
d. polyunsaturated
6.
Peptidoglycan is a polymer of the
alternating sugars
a. glucose and galactose
b. ribose and deoxyribose
c. alanine and cytosine
d. N-acetylglucosamine and N-acetylmuramic
acid
7.
In the β-form of glucose,
a. the hydroxyl group on carbon 1 is below the ring
b. the hydroxyl group on carbon 1 is above
the ring
c. the hydroxyl group on carbon 2 is missing
d. the hydroxyl group on carbons 2 and 3 are missing
8.
The plasma membrane is
a. impermeable to all molecules
b. impermeable to H2O
c. permeable to all molecules
d. selectively permeable
9.
D-amino acids are found in
a. proteins
b. peptidoglycan
c. carbohydrates
d. DNA
10.
The Sec protein secretion system is
used
a. by Gram negative cells to transport proteins
across both membranes
b. to transport proteins across the peptidoglycan
layer of bacterial cells
c. to transport proteins across the plasma
membrane of bacterial cells
d. to transport nutrients into the cells against a
concentration gradient
11. If the
genome of a virus has the following composition 155 A, 133 C, 133 G and 155 U.
What type of nucleic acid is the genome made of?
a. double stranded DNA
b. single stranded RNA
c. single stranded DNA
d. double stranded RNA
12.
Which of the following is NOT a component of the Gram
negative lipopolysaccharide
a. Lipid A
b. core polysaccharide
c. teichoic acid
d. repeating O-side chain
13.
Which of the following
macromolecules are not formed by polymerization
a. lipids
b. carbohydrates
c. proteins
d. nucleic acids
14.
Active transport
a. requires energy input
b. does not require energy input
c. allows H2O to enter the cell
d. requires a concentration gradient
15.
Penicillin acts as an antibiotic by
a. preventing the cross linking of peptidoglycan tetrapeptides
b.
cleaving the glycosidic bonds between N-acetylglucosamine and N-acetylmuramic
acids
c.
preventing the formation of ester linkages in phospholipid synthesis
d.
Cleaving crosslinked peptidoglycan molecules
Part
2 SHORT ANSWER: Read each question carefully and answer each question in the
space provided. Each correct answer is worth 5 points, for a Part 2 total of 45
points.
JUSTIFICATIONS: Again, if you are unsure of an answer, you may write a short explanation next to the question on the test paper.
16. a. True
OR False? Lipids are polar and dissolve in water. This is an important property
for the formation of bacterial membranes.
__FALSE_________
b. True
OR False? Bacterial membranes are fluid, allowing proteins and phospholipids to
move laterally through the membrane.
____TRUE________
17. In the
space below, draw the formation of a β1-4 glycosidic bond between two
glucose molecules using structural formula. Include reactants and products.

18. DNA
and RNA are polymerized in the 5’-3’ direction. What do the 5’ and 3’ numbers
refer to?
___Carbons 5 and 3 on adjacent deoxyribose or ribose sugars.
These carbons are connected through phosphate in a phosphodiester bond
19. a. Fill
in the blanks. A peptide bond is formed between the carboxyl
group of one amino acid and the amino
group of the next amino acid.
b. Fill
in the blank. The start of a protein is called the amino
or N- terminus and the end of a protein is called the carboxyl or C- terminus.
20. a. True
OR False? Peptidoglycan is an almost impermeable barrier that excludes most
nutrients from the cell.
FALSE
b. True
OR False? The outer membrane of Gram negative bacteria is more permeable than
the plasma membrane.
TRUE
21. Fill
in the blanks. DNA contains four nitrogenous bases; the pyrimidines cytosine and thymine,
and the purines adenine and guanine.
22. a. True
OR False? The secondary structure of protein refers to the local folding of
amino acids into structures such as α‑helices and β‑sheets.
TRUE
b. The
quaternary structure of proteins refers to multiple polypeptide subunits coming
together to form a functional protein.
TRUE
23. Fill
in the blanks. In the Gram stain, following decolorization with the alcohol,
Gram negative cells will be colorless,
while Gram positive cells will retain their purple/violet
color. This results from the dehydration of peptidoglycan
in the Gram positive cell wall, which traps the crystal violet-iodine complex
inside the cell.
24. a. Fill
in the blanks. In Gram negative bacteria, the Type II secretion system
transports proteins across the outer
membrane, while the Type I secretion system transports proteins directly from
the cytoplasm to the external
environment.
b. True
OR False? Both Type I and Type II secretion systems require energy in the form
of ATP.
Part
3 SHORT ESSAY: Answer TWO of the following questions in the space
provided. Each correct answer is worth ten points, for a total of 20 points for
Part 3.
25. Using
a schematic diagram describe the structure of peptidoglycan in Gram negative
and Gram positive bacteria. Label the sugars and amino acids, and indicate any
unusual bonds.

26. Describe
the fate of bacterial cells in hypotonic and hypertonic solutions. Describe
what happens to these cells if the cell wall is removed.
Hypotonic solutions are those where solute concentrations are
greater inside the cell than outside the cell. As a result water (which can
move freely through bacterial membrane and cell walls) moves into the cell. Bacterial
cells are protected in hypotonic solutions by the strength of the peptidoglycan
in the cell wall which maintains the integrity of the cell. Even though the
cell membrane expands, the cell wall prevents the cell from lysing. Cells
without cell walls are osmosensitive. In hypotonic solutions, water will move
into the cell, and the cell will expand and eventually burst.
Hypertonic solutions and those where solute concentrations are
greater outside the cell than inside the cell. As a result water moves out of
the cell. Bacterial cells are sensitive to high external solute concentration
because when water moves out of the cell the cytoplasm dehydrates. Even though
the cell wall maintains cell shape, the plasma membrane will shrink away from
the cell wall in a process called plasmolysis and the cell will eventually die.
Cell without cell walls are very sensitive to hypertonic conditions, as water
rushes out of the cell and the cell shrinks and dies.
27. Describe
the structure of deoxyribonucleic acid, including nucleotides (and their
components), bonds between nucleotides and bonds between DNA strands.
In DNA, nucleotides are composed of deoxyribose, phosphate and one
of four nitrogenous bases (adenine, cytosine, guanine and thymine)
Nucleotides are linked by phophodiester bonds forming a sugar
phosphate backbone where deoxyribose sugars are linked by phosphate groups
through carbons 3 and 5. The nitrogenous base is attached to carbon 1 of
deoxyribose
DNA is double stranded, and the two strands are linked though
hydrogen bonding between the nitrogenous bases. A only binds with T (2
H-bonds), while C only binds with G (3 H-bonds)
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